5x-2(x+1)=3(7-2x)

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Solution for 5x-2(x+1)=3(7-2x) equation: 



5x-2(x+1)=3(7-2x)

We move all terms to the left:

5x-2(x+1)-(3(7-2x))=0

We add all the numbers together, and all the variables

5x-2(x+1)-(3(-2x+7))=0

We multiply parentheses

5x-2x-(3(-2x+7))-2=0



We calculate terms in parentheses: -(3(-2x+7)), so:

3(-2x+7)

We multiply parentheses

-6x+21

Back to the equation:

-(-6x+21)



We add all the numbers together, and all the variables

3x-(-6x+21)-2=0

We get rid of parentheses

3x+6x-21-2=0

We add all the numbers together, and all the variables

9x-23=0

We move all terms containing x to the left, all other terms to the right

9x=23

x=23/9

x=2+5/9

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