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5x-2(x+3)=-3(2-x)
We move all terms to the left:
5x-2(x+3)-(-3(2-x))=0
We add all the numbers together, and all the variables
5x-2(x+3)-(-3(-1x+2))=0
We multiply parentheses
5x-2x-(-3(-1x+2))-6=0
We calculate terms in parentheses: -(-3(-1x+2)), so:We add all the numbers together, and all the variables
-3(-1x+2)
We multiply parentheses
3x-6
Back to the equation:
-(3x-6)
3x-(3x-6)-6=0
We get rid of parentheses
3x-3x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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