5x-2(x+4)=1-3(8x-4)

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Solution for 5x-2(x+4)=1-3(8x-4) equation: 



5x-2(x+4)=1-3(8x-4)

We move all terms to the left:

5x-2(x+4)-(1-3(8x-4))=0

We multiply parentheses

5x-2x-(1-3(8x-4))-8=0



We calculate terms in parentheses: -(1-3(8x-4)), so:

1-3(8x-4)

determiningTheFunctionDomain
-3(8x-4)+1

We multiply parentheses

-24x+12+1

We add all the numbers together, and all the variables

-24x+13

Back to the equation:

-(-24x+13)



We add all the numbers together, and all the variables

3x-(-24x+13)-8=0

We get rid of parentheses

3x+24x-13-8=0

We add all the numbers together, and all the variables

27x-21=0

We move all terms containing x to the left, all other terms to the right

27x=21

x=21/27

x=7/9

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