5x-2(x+4)=14x+13(8-3x)-42

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Solution for 5x-2(x+4)=14x+13(8-3x)-42 equation: 



5x-2(x+4)=14x+13(8-3x)-42

We move all terms to the left:

5x-2(x+4)-(14x+13(8-3x)-42)=0

We add all the numbers together, and all the variables

5x-2(x+4)-(14x+13(-3x+8)-42)=0

We multiply parentheses

5x-2x-(14x+13(-3x+8)-42)-8=0



We calculate terms in parentheses: -(14x+13(-3x+8)-42), so:

14x+13(-3x+8)-42

We multiply parentheses

14x-39x+104-42

We add all the numbers together, and all the variables

-25x+62

Back to the equation:

-(-25x+62)



We add all the numbers together, and all the variables

3x-(-25x+62)-8=0

We get rid of parentheses

3x+25x-62-8=0

We add all the numbers together, and all the variables

28x-70=0

We move all terms containing x to the left, all other terms to the right

28x=70

x=70/28

x=2+1/2

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