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5x-2(x-5)=3(x+1)+2
We move all terms to the left:
5x-2(x-5)-(3(x+1)+2)=0
We multiply parentheses
5x-2x-(3(x+1)+2)+10=0
We calculate terms in parentheses: -(3(x+1)+2), so:We add all the numbers together, and all the variables
3(x+1)+2
We multiply parentheses
3x+3+2
We add all the numbers together, and all the variables
3x+5
Back to the equation:
-(3x+5)
3x-(3x+5)+10=0
We get rid of parentheses
3x-3x-5+10=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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