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5x-2/9x-6=1
We move all terms to the left:
5x-2/9x-6-(1)=0
Domain of the equation: 9x!=0We add all the numbers together, and all the variables
x!=0/9
x!=0
x∈R
5x-2/9x-7=0
We multiply all the terms by the denominator
5x*9x-7*9x-2=0
Wy multiply elements
45x^2-63x-2=0
a = 45; b = -63; c = -2;
Δ = b2-4ac
Δ = -632-4·45·(-2)
Δ = 4329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4329}=\sqrt{9*481}=\sqrt{9}*\sqrt{481}=3\sqrt{481}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-3\sqrt{481}}{2*45}=\frac{63-3\sqrt{481}}{90} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+3\sqrt{481}}{2*45}=\frac{63+3\sqrt{481}}{90} $
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