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5x-2=x(2x-1)
We move all terms to the left:
5x-2-(x(2x-1))=0
We calculate terms in parentheses: -(x(2x-1)), so:We get rid of parentheses
x(2x-1)
We multiply parentheses
2x^2-1x
Back to the equation:
-(2x^2-1x)
-2x^2+5x+1x-2=0
We add all the numbers together, and all the variables
-2x^2+6x-2=0
a = -2; b = 6; c = -2;
Δ = b2-4ac
Δ = 62-4·(-2)·(-2)
Δ = 20
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20}=\sqrt{4*5}=\sqrt{4}*\sqrt{5}=2\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{5}}{2*-2}=\frac{-6-2\sqrt{5}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{5}}{2*-2}=\frac{-6+2\sqrt{5}}{-4} $
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