5x-2y=4;x+3y=0

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Remember to put linear equations with variables x and y.
for example:
2x+y=8
x+3y=14

Solution for 5x-2y=4;x+3y=0 system of equations: 


  • /| 5*x-(2*y)-4 = 0| x+3*y = 0
  • We try to solve the equation: 5*x-(2*y)-4 = 0
  • 5*x-2*y-4 = 0 // - 5*x-4
  • -2*y = -(5*x-4) // : -2
  • y = (-(5*x-4))/(-2)
  • y = (4-(5*x))/(-2)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 3*((4-(5*x))/(-2))+x = 0| y = (4-(5*x))/(-2)
  • (3*(4-5*x))/(-2)+x = 0
  • 17/2*x-6 = 0
  • 17/2*x-6 = 0 // + 6
  • 17/2*x = 6 // : 17/2
  • x = 6/17/2
  • x = 12/17
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (4-(5*x))/(-2): 
  • y = (4-(12/17*5))/(-2)
  • y = (4-60/17)/(-2)
  • y = 8/17/(-2)
  • y = -4/17
  • We get a system of equations:
  • /| y = -4/17| x = 12/17

 

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