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5x-3(2x+1)-4=3(2x+1)+4
We move all terms to the left:
5x-3(2x+1)-4-(3(2x+1)+4)=0
We multiply parentheses
5x-6x-(3(2x+1)+4)-3-4=0
We calculate terms in parentheses: -(3(2x+1)+4), so:We add all the numbers together, and all the variables
3(2x+1)+4
We multiply parentheses
6x+3+4
We add all the numbers together, and all the variables
6x+7
Back to the equation:
-(6x+7)
-1x-(6x+7)-7=0
We get rid of parentheses
-1x-6x-7-7=0
We add all the numbers together, and all the variables
-7x-14=0
We move all terms containing x to the left, all other terms to the right
-7x=14
x=14/-7
x=-2
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