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5x-3(2x+5)=7(2x+1)-6
We move all terms to the left:
5x-3(2x+5)-(7(2x+1)-6)=0
We multiply parentheses
5x-6x-(7(2x+1)-6)-15=0
We calculate terms in parentheses: -(7(2x+1)-6), so:We add all the numbers together, and all the variables
7(2x+1)-6
We multiply parentheses
14x+7-6
We add all the numbers together, and all the variables
14x+1
Back to the equation:
-(14x+1)
-1x-(14x+1)-15=0
We get rid of parentheses
-1x-14x-1-15=0
We add all the numbers together, and all the variables
-15x-16=0
We move all terms containing x to the left, all other terms to the right
-15x=16
x=16/-15
x=-1+1/15
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