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5x-3(3-x)=21+5(2x+3)
We move all terms to the left:
5x-3(3-x)-(21+5(2x+3))=0
We add all the numbers together, and all the variables
5x-3(-1x+3)-(21+5(2x+3))=0
We multiply parentheses
5x+3x-(21+5(2x+3))-9=0
We calculate terms in parentheses: -(21+5(2x+3)), so:We add all the numbers together, and all the variables
21+5(2x+3)
determiningTheFunctionDomain 5(2x+3)+21
We multiply parentheses
10x+15+21
We add all the numbers together, and all the variables
10x+36
Back to the equation:
-(10x+36)
8x-(10x+36)-9=0
We get rid of parentheses
8x-10x-36-9=0
We add all the numbers together, and all the variables
-2x-45=0
We move all terms containing x to the left, all other terms to the right
-2x=45
x=45/-2
x=-22+1/2
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