5x-3(x+1)=2(x+3)-9

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Solution for 5x-3(x+1)=2(x+3)-9 equation:


Simplifying
5x + -3(x + 1) = 2(x + 3) + -9

Reorder the terms:
5x + -3(1 + x) = 2(x + 3) + -9
5x + (1 * -3 + x * -3) = 2(x + 3) + -9
5x + (-3 + -3x) = 2(x + 3) + -9

Reorder the terms:
-3 + 5x + -3x = 2(x + 3) + -9

Combine like terms: 5x + -3x = 2x
-3 + 2x = 2(x + 3) + -9

Reorder the terms:
-3 + 2x = 2(3 + x) + -9
-3 + 2x = (3 * 2 + x * 2) + -9
-3 + 2x = (6 + 2x) + -9

Reorder the terms:
-3 + 2x = 6 + -9 + 2x

Combine like terms: 6 + -9 = -3
-3 + 2x = -3 + 2x

Add '3' to each side of the equation.
-3 + 3 + 2x = -3 + 3 + 2x

Combine like terms: -3 + 3 = 0
0 + 2x = -3 + 3 + 2x
2x = -3 + 3 + 2x

Combine like terms: -3 + 3 = 0
2x = 0 + 2x
2x = 2x

Add '-2x' to each side of the equation.
2x + -2x = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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