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5x-3(x+2)=7(x+5)
We move all terms to the left:
5x-3(x+2)-(7(x+5))=0
We multiply parentheses
5x-3x-(7(x+5))-6=0
We calculate terms in parentheses: -(7(x+5)), so:We add all the numbers together, and all the variables
7(x+5)
We multiply parentheses
7x+35
Back to the equation:
-(7x+35)
2x-(7x+35)-6=0
We get rid of parentheses
2x-7x-35-6=0
We add all the numbers together, and all the variables
-5x-41=0
We move all terms containing x to the left, all other terms to the right
-5x=41
x=41/-5
x=-8+1/5
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