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5x-3(x+4)=3x+7(x-5)
We move all terms to the left:
5x-3(x+4)-(3x+7(x-5))=0
We multiply parentheses
5x-3x-(3x+7(x-5))-12=0
We calculate terms in parentheses: -(3x+7(x-5)), so:We add all the numbers together, and all the variables
3x+7(x-5)
We multiply parentheses
3x+7x-35
We add all the numbers together, and all the variables
10x-35
Back to the equation:
-(10x-35)
2x-(10x-35)-12=0
We get rid of parentheses
2x-10x+35-12=0
We add all the numbers together, and all the variables
-8x+23=0
We move all terms containing x to the left, all other terms to the right
-8x=-23
x=-23/-8
x=2+7/8
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