5x-3(x-2)=4(-x-1)

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Solution for 5x-3(x-2)=4(-x-1) equation: 



5x-3(x-2)=4(-x-1)

We move all terms to the left:

5x-3(x-2)-(4(-x-1))=0

We add all the numbers together, and all the variables

5x-3(x-2)-(4(-1x-1))=0

We multiply parentheses

5x-3x-(4(-1x-1))+6=0



We calculate terms in parentheses: -(4(-1x-1)), so:

4(-1x-1)

We multiply parentheses

-4x-4

Back to the equation:

-(-4x-4)



We add all the numbers together, and all the variables

2x-(-4x-4)+6=0

We get rid of parentheses

2x+4x+4+6=0

We add all the numbers together, and all the variables

6x+10=0

We move all terms containing x to the left, all other terms to the right

6x=-10

x=-10/6

x=-1+2/3

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