5x-3(x-4)=8+4x+12

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Solution for 5x-3(x-4)=8+4x+12 equation: 



5x-3(x-4)=8+4x+12

We move all terms to the left:

5x-3(x-4)-(8+4x+12)=0

We add all the numbers together, and all the variables

5x-3(x-4)-(4x+20)=0

We multiply parentheses

5x-3x-(4x+20)+12=0

We get rid of parentheses

5x-3x-4x-20+12=0

We add all the numbers together, and all the variables

-2x-8=0

We move all terms containing x to the left, all other terms to the right

-2x=8

x=8/-2

x=-4

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