5x-3(x-4)=8+4x+12

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Solution for 5x-3(x-4)=8+4x+12 equation:



5x-3(x-4)=8+4x+12
We move all terms to the left:
5x-3(x-4)-(8+4x+12)=0
We add all the numbers together, and all the variables
5x-3(x-4)-(4x+20)=0
We multiply parentheses
5x-3x-(4x+20)+12=0
We get rid of parentheses
5x-3x-4x-20+12=0
We add all the numbers together, and all the variables
-2x-8=0
We move all terms containing x to the left, all other terms to the right
-2x=8
x=8/-2
x=-4

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