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5x-3(x-5)=-9+4x+12
We move all terms to the left:
5x-3(x-5)-(-9+4x+12)=0
We add all the numbers together, and all the variables
5x-3(x-5)-(4x+3)=0
We multiply parentheses
5x-3x-(4x+3)+15=0
We get rid of parentheses
5x-3x-4x-3+15=0
We add all the numbers together, and all the variables
-2x+12=0
We move all terms containing x to the left, all other terms to the right
-2x=-12
x=-12/-2
x=+6
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