5x-3+6+1=5-2(x+4)

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Solution for 5x-3+6+1=5-2(x+4) equation: 



5x-3+6+1=5-2(x+4)

We move all terms to the left:

5x-3+6+1-(5-2(x+4))=0

We add all the numbers together, and all the variables

5x-(5-2(x+4))+4=0



We calculate terms in parentheses: -(5-2(x+4)), so:

5-2(x+4)

determiningTheFunctionDomain
-2(x+4)+5

We multiply parentheses

-2x-8+5

We add all the numbers together, and all the variables

-2x-3

Back to the equation:

-(-2x-3)



We get rid of parentheses

5x+2x+3+4=0

We add all the numbers together, and all the variables

7x+7=0

We move all terms containing x to the left, all other terms to the right

7x=-7

x=-7/7

x=-1

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