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5x-3=(3x+2)(3x-1)
We move all terms to the left:
5x-3-((3x+2)(3x-1))=0
We multiply parentheses ..
-((+9x^2-3x+6x-2))+5x-3=0
We calculate terms in parentheses: -((+9x^2-3x+6x-2)), so:We add all the numbers together, and all the variables
(+9x^2-3x+6x-2)
We get rid of parentheses
9x^2-3x+6x-2
We add all the numbers together, and all the variables
9x^2+3x-2
Back to the equation:
-(9x^2+3x-2)
5x-(9x^2+3x-2)-3=0
We get rid of parentheses
-9x^2+5x-3x+2-3=0
We add all the numbers together, and all the variables
-9x^2+2x-1=0
a = -9; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·(-9)·(-1)
Δ = -32
Delta is less than zero, so there is no solution for the equation
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