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x in (-oo:+oo)
5*x-3 = 10*((1/2)*x+1/5) // - 10*((1/2)*x+1/5)
5*x-(10*((1/2)*x+1/5))-3 = 0
5*x-10*((1/2)*x+1/5)-3 = 0
5*x-10*(1/2*x+1/5)-3 = 0
5*x-10*(1/2*x+1/5)-3 = 0
-3-2 = 0
-5 = 0
-5 = 0
x belongs to the empty set
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