5x-3x(x-5)=-4(x-2)(x-5)+24

Solution for 5x-3x(x-5)=-4(x-2)(x-5)+24 equation:

5x-3x(x-5)=-4(x-2)(x-5)+24

We move all terms to the left:

5x-3x(x-5)-(-4(x-2)(x-5)+24)=0

We multiply parentheses

-3x^2+5x+15x-(-4(x-2)(x-5)+24)=0

We multiply parentheses ..

-3x^2-(-4(+x^2-5x-2x+10)+24)+5x+15x=0


We calculate terms in parentheses: -(-4(+x^2-5x-2x+10)+24), so:

-4(+x^2-5x-2x+10)+24

We multiply parentheses

-4x^2+20x+8x-40+24

We add all the numbers together, and all the variables

-4x^2+28x-16

Back to the equation:

-(-4x^2+28x-16)


We add all the numbers together, and all the variables

-3x^2-(-4x^2+28x-16)+20x=0

We get rid of parentheses

-3x^2+4x^2-28x+20x+16=0

We add all the numbers together, and all the variables

x^2-8x+16=0

a = 1; b = -8; c = +16;
Δ = b2-4ac
Δ = -82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{8}{2}=4$