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5x-3x+12=2(x+6)
We move all terms to the left:
5x-3x+12-(2(x+6))=0
We add all the numbers together, and all the variables
2x-(2(x+6))+12=0
We calculate terms in parentheses: -(2(x+6)), so:We get rid of parentheses
2(x+6)
We multiply parentheses
2x+12
Back to the equation:
-(2x+12)
2x-2x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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