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5x-4(1-3x)=4x-(x+11)
We move all terms to the left:
5x-4(1-3x)-(4x-(x+11))=0
We add all the numbers together, and all the variables
5x-4(-3x+1)-(4x-(x+11))=0
We multiply parentheses
5x+12x-(4x-(x+11))-4=0
We calculate terms in parentheses: -(4x-(x+11)), so:We add all the numbers together, and all the variables
4x-(x+11)
We get rid of parentheses
4x-x-11
We add all the numbers together, and all the variables
3x-11
Back to the equation:
-(3x-11)
17x-(3x-11)-4=0
We get rid of parentheses
17x-3x+11-4=0
We add all the numbers together, and all the variables
14x+7=0
We move all terms containing x to the left, all other terms to the right
14x=-7
x=-7/14
x=-1/2
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