5x-4(20-x)=24+5x-3(4-x)

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Solution for 5x-4(20-x)=24+5x-3(4-x) equation: 



5x-4(20-x)=24+5x-3(4-x)

We move all terms to the left:

5x-4(20-x)-(24+5x-3(4-x))=0

We add all the numbers together, and all the variables

5x-4(-1x+20)-(24+5x-3(-1x+4))=0

We multiply parentheses

5x+4x-(24+5x-3(-1x+4))-80=0



We calculate terms in parentheses: -(24+5x-3(-1x+4)), so:

24+5x-3(-1x+4)

determiningTheFunctionDomain
5x-3(-1x+4)+24

We multiply parentheses

5x+3x-12+24

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We add all the numbers together, and all the variables

9x-(8x+12)-80=0

We get rid of parentheses

9x-8x-12-80=0

We add all the numbers together, and all the variables

x-92=0

We move all terms containing x to the left, all other terms to the right

x=92

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