5x-4(3-2x)=3(x-3)-53

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Solution for 5x-4(3-2x)=3(x-3)-53 equation: 



5x-4(3-2x)=3(x-3)-53

We move all terms to the left:

5x-4(3-2x)-(3(x-3)-53)=0

We add all the numbers together, and all the variables

5x-4(-2x+3)-(3(x-3)-53)=0

We multiply parentheses

5x+8x-(3(x-3)-53)-12=0



We calculate terms in parentheses: -(3(x-3)-53), so:

3(x-3)-53

We multiply parentheses

3x-9-53

We add all the numbers together, and all the variables

3x-62

Back to the equation:

-(3x-62)



We add all the numbers together, and all the variables

13x-(3x-62)-12=0

We get rid of parentheses

13x-3x+62-12=0

We add all the numbers together, and all the variables

10x+50=0

We move all terms containing x to the left, all other terms to the right

10x=-50

x=-50/10

x=-5

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