5x-4(3x-7)=3x(-9x+5)

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Solution for 5x-4(3x-7)=3x(-9x+5) equation: 



5x-4(3x-7)=3x(-9x+5)

We move all terms to the left:

5x-4(3x-7)-(3x(-9x+5))=0

We multiply parentheses

5x-12x-(3x(-9x+5))+28=0



We calculate terms in parentheses: -(3x(-9x+5)), so:

3x(-9x+5)

We multiply parentheses

-27x^2+15x

Back to the equation:

-(-27x^2+15x)



We add all the numbers together, and all the variables

-(-27x^2+15x)-7x+28=0

We get rid of parentheses

27x^2-15x-7x+28=0

We add all the numbers together, and all the variables

27x^2-22x+28=0

a = 27; b = -22; c = +28;
Δ = b2-4ac
Δ = -222-4·27·28
Δ = -2540
Delta is less than zero, so there is no solution for the equation

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