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5x-4/2x-3=10(3-x)/17x-4x
We move all terms to the left:
5x-4/2x-3-(10(3-x)/17x-4x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 17x-4x)!=0We add all the numbers together, and all the variables
x∈R
5x-4/2x-(10(-1x+3)/17x-4x)-3=0
We calculate fractions
5x+(-68x-4x))/(34x^2-4x))+(-(10(-1x+3)*2x)/(34x^2-4x))-3=0
We add all the numbers together, and all the variables
5x+(-72x))/(34x^2-4x))+(-(10(-1x+3)*2x)/(34x^2-4x))-3=0
We multiply all the terms by the denominator
5x*(34x^2+(-72x))-4x))+(-(10(-1x+3)*2x)-4x)-3)*(34x^2=0
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