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5x-4=(35-x)/4
We move all terms to the left:
5x-4-((35-x)/4)=0
We add all the numbers together, and all the variables
5x-((-1x+35)/4)-4=0
We multiply all the terms by the denominator
5x*4)-((-1x+35)-4*4)=0
We add all the numbers together, and all the variables
5x*4)-((-1x+35)=0
Wy multiply elements
20x^2=0
a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{40}=0$
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