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5x-4=3-2(3-2x)
We move all terms to the left:
5x-4-(3-2(3-2x))=0
We add all the numbers together, and all the variables
5x-(3-2(-2x+3))-4=0
We calculate terms in parentheses: -(3-2(-2x+3)), so:We get rid of parentheses
3-2(-2x+3)
determiningTheFunctionDomain -2(-2x+3)+3
We multiply parentheses
4x-6+3
We add all the numbers together, and all the variables
4x-3
Back to the equation:
-(4x-3)
5x-4x+3-4=0
We add all the numbers together, and all the variables
x-1=0
We move all terms containing x to the left, all other terms to the right
x=1
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