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5x-6+7=15/3x
We move all terms to the left:
5x-6+7-(15/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5x-(+15/3x)-6+7=0
We add all the numbers together, and all the variables
5x-(+15/3x)+1=0
We get rid of parentheses
5x-15/3x+1=0
We multiply all the terms by the denominator
5x*3x+1*3x-15=0
Wy multiply elements
15x^2+3x-15=0
a = 15; b = 3; c = -15;
Δ = b2-4ac
Δ = 32-4·15·(-15)
Δ = 909
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{909}=\sqrt{9*101}=\sqrt{9}*\sqrt{101}=3\sqrt{101}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{101}}{2*15}=\frac{-3-3\sqrt{101}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{101}}{2*15}=\frac{-3+3\sqrt{101}}{30} $
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