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5x-6/3(15+3x)=10-(15x-1)
We move all terms to the left:
5x-6/3(15+3x)-(10-(15x-1))=0
Domain of the equation: 3(15+3x)!=0We add all the numbers together, and all the variables
x∈R
5x-6/3(3x+15)-(10-(15x-1))=0
We multiply all the terms by the denominator
5x*3(3x+15)-((10-(15x-1)))*3(3x+15)-6=0
We calculate terms in parentheses: -((10-(15x-1)))*3(3x+15), so:Wy multiply elements
(10-(15x-1)))*3(3x+15
15x^2(3-((10-(15x-1)))*3(3x+15)-6=0
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