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5x-6=2(2x^2)
We move all terms to the left:
5x-6-(2(2x^2))=0
determiningTheFunctionDomain 5x-22x^2-6=0
We add all the numbers together, and all the variables
-22x^2+5x-6=0
a = -22; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·(-22)·(-6)
Δ = -503
Delta is less than zero, so there is no solution for the equation
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