5x-7+4x+12=6(x-2)

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Solution for 5x-7+4x+12=6(x-2) equation: 



5x-7+4x+12=6(x-2)

We move all terms to the left:

5x-7+4x+12-(6(x-2))=0

We add all the numbers together, and all the variables

9x-(6(x-2))+5=0



We calculate terms in parentheses: -(6(x-2)), so:

6(x-2)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We get rid of parentheses

9x-6x+12+5=0

We add all the numbers together, and all the variables

3x+17=0

We move all terms containing x to the left, all other terms to the right

3x=-17

x=-17/3

x=-5+2/3

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