5x-7/7x-5=x-5/2x-3

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Solution for 5x-7/7x-5=x-5/2x-3 equation: 



5x-7/7x-5=x-5/2x-3

We move all terms to the left:

5x-7/7x-5-(x-5/2x-3)=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R





Domain of the equation: 2x-3)!=0

x∈R



We get rid of parentheses

5x-7/7x-x+5/2x+3-5=0

We calculate fractions


5x-x+(-14x)/14x^2+35x/14x^2+3-5=0

We add all the numbers together, and all the variables

4x+(-14x)/14x^2+35x/14x^2-2=0

We multiply all the terms by the denominator


4x*14x^2+(-14x)+35x-2*14x^2=0

We add all the numbers together, and all the variables

35x+4x*14x^2+(-14x)-2*14x^2=0

Wy multiply elements

56x^3-28x^2+35x+(-14x)=0

We get rid of parentheses

56x^3-28x^2+35x-14x=0

We do not support expression: x^3

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