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5x-8/2x=1
We move all terms to the left:
5x-8/2x-(1)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
5x*2x-1*2x-8=0
Wy multiply elements
10x^2-2x-8=0
a = 10; b = -2; c = -8;
Δ = b2-4ac
Δ = -22-4·10·(-8)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-18}{2*10}=\frac{-16}{20} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+18}{2*10}=\frac{20}{20} =1 $
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