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5x-8=4-(x+2)
We move all terms to the left:
5x-8-(4-(x+2))=0
We calculate terms in parentheses: -(4-(x+2)), so:We get rid of parentheses
4-(x+2)
determiningTheFunctionDomain -(x+2)+4
We get rid of parentheses
-x-2+4
We add all the numbers together, and all the variables
-1x+2
Back to the equation:
-(-1x+2)
5x+1x-2-8=0
We add all the numbers together, and all the variables
6x-10=0
We move all terms containing x to the left, all other terms to the right
6x=10
x=10/6
x=1+2/3
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