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5x-9=3(x-2)x
We move all terms to the left:
5x-9-(3(x-2)x)=0
We calculate terms in parentheses: -(3(x-2)x), so:We get rid of parentheses
3(x-2)x
We multiply parentheses
3x^2-6x
Back to the equation:
-(3x^2-6x)
-3x^2+5x+6x-9=0
We add all the numbers together, and all the variables
-3x^2+11x-9=0
a = -3; b = 11; c = -9;
Δ = b2-4ac
Δ = 112-4·(-3)·(-9)
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{13}}{2*-3}=\frac{-11-\sqrt{13}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{13}}{2*-3}=\frac{-11+\sqrt{13}}{-6} $
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