If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
2*x+1 = 0
4*x+2 = 0
2*x+1 = 0
2*x+1 = 0
2*x+1 = 0 // - 1
2*x = -1 // : 2
x = -1/2
4*x+2 = 0
4*x+2 = 0
4*x+2 = 0 // - 2
4*x = -2 // : 4
x = -2/4
x = -1/2
x in (-oo:-1/2) U (-1/2:+oo)
(5*x)/(2*x+1)+8/(4*x+2) = 8/3 // - 8/3
(5*x)/(2*x+1)+8/(4*x+2)-(8/3) = 0
(5*x)/(2*x+1)+8/(4*x+2)-8/3 = 0
(3*5*x*(4*x+2))/(3*(2*x+1)*(4*x+2))+(3*8*(2*x+1))/(3*(2*x+1)*(4*x+2))+(-8*(2*x+1)*(4*x+2))/(3*(2*x+1)*(4*x+2)) = 0
3*5*x*(4*x+2)+3*8*(2*x+1)-8*(2*x+1)*(4*x+2) = 0
60*x^2-64*x^2+78*x-64*x-16+24 = 0
14*x-4*x^2+8 = 0
14*x-4*x^2+8 = 0
2*(7*x-2*x^2+4) = 0
7*x-2*x^2+4 = 0
DELTA = 7^2-(-2*4*4)
DELTA = 81
DELTA > 0
x = (81^(1/2)-7)/(-2*2) or x = (-81^(1/2)-7)/(-2*2)
x = -1/2 or x = 4
2*(x+1/2)*(x-4) = 0
(2*(x+1/2)*(x-4))/(3*(2*x+1)*(4*x+2)) = 0
(2*(x+1/2)*(x-4))/(3*(2*x+1)*(4*x+2)) = 0 // * 3*(2*x+1)*(4*x+2)
2*(x+1/2)*(x-4) = 0
( x+1/2 )
x+1/2 = 0 // - 1/2
x = -1/2
( x-4 )
x-4 = 0 // + 4
x = 4
x in { -1/2}
x = 4
| -4x+5/3+2=-5/2x | | 5(5x+4)=120 | | 5x/2x+1+8/4x+2=8/3 | | x=2yz+2yx+2zx | | 4x+106=14x-14 | | 1-3x=10x-41 | | t^2+45t=0 | | -4x+5/3+2=-5x/2 | | 5(3x-4)-5=5(x-5)+40 | | 3x+12=98-6x | | 9x-(5x+3)=2x-17 | | 118-6x=4x+3 | | (x-1/2)+(x+2/3)=x | | -x^2-4x+6=y | | 2n^2-12n+18=0 | | 3x-9=x | | 4/n=3/7/30 | | 0=-x^2+4x-6 | | y=-x^2+4x-6 | | 5+6=2x+45 | | x(x+2)=4(x+2) | | f(x)=x^2-14x-32 | | 2(12/x)=x-2 | | x^3+4x-320=0 | | 1/15x=3 | | 3(x-3)=4(3x-9) | | x^2-2x+6=20 | | 10-10x=166-38x | | -3=17-5c | | 9+4b=-15 | | 4d+7=6r | | 8b^5+5b^2-4b^5-5b^2= |