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5x/(6x-18)=1/(x-3)
We move all terms to the left:
5x/(6x-18)-(1/(x-3))=0
Domain of the equation: (6x-18)!=0
We move all terms containing x to the left, all other terms to the right
6x!=18
x!=18/6
x!=3
x∈R
Domain of the equation: (x-3))!=0We calculate fractions
x∈R
(-10x^2)/((6x-18)*(x-3)))+(-(1*(6x-18))/((6x-18)*(x-3)))=0
We calculate terms in parentheses: -(1*(6x-18))/((6x-18)*(x-3))), so:We multiply all the terms by the denominator
1*(6x-18))/((6x-18)*(x-3))
We multiply all the terms by the denominator
1*(6x-18))
Back to the equation:
-(1*(6x-18)))
(-10x^2)-((1*(6x-18))))*((6x-18)*(x-3)))+(=0
We get rid of parentheses
-10x^2-((1*(6x-18))))*((6x-18)*(x-3)))+(=0
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