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D( x )
x+1 = 0
x+1 = 0
x+1 = 0
x+1 = 0 // - 1
x = -1
x in (-oo:-1) U (-1:+oo)
(5*x)/(x+1) = 2-(5/(x+1)) // - 2-(5/(x+1))
(5*x)/(x+1)+5/(x+1)-2 = 0
(5*x)/(x+1)+5/(x+1)+(-2*(x+1))/(x+1) = 0
5*x-2*(x+1)+5 = 0
5*x-2*x-2+5 = 0
3*x+3 = 0
(3*x+3)/(x+1) = 0
(3*x+3)/(x+1) = 0 // * x+1
3*x+3 = 0
3*x+3 = 0 // - 3
3*x = -3 // : 3
x = -3/3
x = -1
x in { -1}
x belongs to the empty set
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