5x/(x-4)=20/(x-4)+7

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Solution for 5x/(x-4)=20/(x-4)+7 equation: 


D( x )

x-4 = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:4) U (4:+oo)

(5*x)/(x-4) = 20/(x-4)+7 // - 20/(x-4)+7

(5*x)/(x-4)-(20/(x-4))-7 = 0

(5*x)/(x-4)-20*(x-4)^-1-7 = 0

(5*x)/(x-4)-20/(x-4)-7 = 0

(5*x)/(x-4)-20/(x-4)+(-7*(x-4))/(x-4) = 0

5*x-7*(x-4)-20 = 0

5*x-7*x-20+28 = 0

8-2*x = 0

(8-2*x)/(x-4) = 0

(8-2*x)/(x-4) = 0 // * x-4

8-2*x = 0

8-2*x = 0 // - 8

-2*x = -8 // : -2

x = -8/(-2)

x = 4

x in { 4} 

x belongs to the empty set

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