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5x/14x+3=1/x
We move all terms to the left:
5x/14x+3-(1/x)=0
Domain of the equation: 14x!=0
x!=0/14
x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5x/14x-(+1/x)+3=0
We get rid of parentheses
5x/14x-1/x+3=0
We calculate fractions
5x^2/14x^2+(-14x)/14x^2+3=0
We multiply all the terms by the denominator
5x^2+(-14x)+3*14x^2=0
Wy multiply elements
5x^2+42x^2+(-14x)=0
We get rid of parentheses
5x^2+42x^2-14x=0
We add all the numbers together, and all the variables
47x^2-14x=0
a = 47; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·47·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*47}=\frac{0}{94} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*47}=\frac{28}{94} =14/47 $
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