5x/2x+6=7x/4x-8

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Solution for 5x/2x+6=7x/4x-8 equation: 



5x/2x+6=7x/4x-8

We move all terms to the left:

5x/2x+6-(7x/4x-8)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 4x-8)!=0

x∈R



We get rid of parentheses

5x/2x-7x/4x+8+6=0

We calculate fractions


(-14x^2)/8x^2+20x^2/8x^2+8+6=0

We add all the numbers together, and all the variables

(-14x^2)/8x^2+20x^2/8x^2+14=0

We multiply all the terms by the denominator


(-14x^2)+20x^2+14*8x^2=0

We add all the numbers together, and all the variables

20x^2+(-14x^2)+14*8x^2=0

Wy multiply elements

20x^2+(-14x^2)+112x^2=0

We get rid of parentheses

20x^2-14x^2+112x^2=0

We add all the numbers together, and all the variables

118x^2=0

a = 118; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·118·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{236}=0$

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