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5x/3-6+2(x+2)=2(x+4)
We move all terms to the left:
5x/3-6+2(x+2)-(2(x+4))=0
We multiply parentheses
5x/3+2x-(2(x+4))+4-6=0
We multiply all the terms by the denominator
5x+2x*3-((2(x+4)))*3+4*3-6*3=0
We add all the numbers together, and all the variables
5x+2x*3-((2(x+4)))*3-6=0
Wy multiply elements
5x+6x-((2(x+4)))*3-6=0
We add all the numbers together, and all the variables
11x-((2(x+4)))*3-6=0
We move all terms containing x to the left, all other terms to the right
11x-((2(x+4)))*3=6
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