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5x/4-2x/3=5/4-x12
We move all terms to the left:
5x/4-2x/3-(5/4-x12)=0
Domain of the equation: 4-x12)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-x12)!=-4
x!=-4/1
x!=-4
x∈R
-(-1x^12+5/4)+5x/4-2x/3=0
We get rid of parentheses
1x^12+5x/4-2x/3-5/4=0
We calculate fractions
There is no solution for this equation
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