5x/4-3/x=2

Solution for 5x/4-3/x=2 equation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(5*x)/4-(3/x) = 2 // - 2

(5*x)/4-(3/x)-2 = 0

(5*x)/4-3*x^-1-2 = 0

5/4*x^1-3*x^-1-2*x^0 = 0

(5/4*x^2-2*x^1-3*x^0)/(x^1) = 0 // * x^2

x^1*(5/4*x^2-2*x^1-3*x^0) = 0

x^1

(5/4)*x^2-2*x-3 = 0

(5/4)*x^2-2*x-3 = 0

DELTA = (-2)^2-(-3*4*(5/4))

DELTA = 19

DELTA > 0

x = (19^(1/2)+2)/(2*(5/4)) or x = (2-19^(1/2))/(2*(5/4))

x = 2/5*(19^(1/2)+2) or x = 2/5*(2-19^(1/2))

x in { 2/5*(2-19^(1/2)), 2/5*(19^(1/2)+2)} 

x in { 2/5*(2-19^(1/2)), 2/5*(19^(1/2)+2) }