5x/4=3+(x-3)/2

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Solution for 5x/4=3+(x-3)/2 equation: 



5x/4=3+(x-3)/2

We move all terms to the left:

5x/4-(3+(x-3)/2)=0

We calculate fractions


10x^2/()+(-(3+(x-3)*4)/()=0



We calculate terms in parentheses: +(-(3+(x-3)*4)/(), so:

-(3+(x-3)*4)/(

We multiply all the terms by the denominator


-(3+(x-3)*4)



We calculate terms in parentheses: -(3+(x-3)*4), so:

3+(x-3)*4

determiningTheFunctionDomain
(x-3)*4+3

We multiply parentheses

4x-12+3

We add all the numbers together, and all the variables

4x-9

Back to the equation:

-(4x-9)



We get rid of parentheses

-4x+9

Back to the equation:

+(-4x+9)



We get rid of parentheses

10x^2/()-4x+9=0

We multiply all the terms by the denominator


10x^2-4x*()+9*()=0

We add all the numbers together, and all the variables

10x^2-4x*()=0

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