5x/x*x-4=10/x*x-4-2/x+2

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Solution for 5x/x*x-4=10/x*x-4-2/x+2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

((5*x)/x)*x-4 = (10/x)*x-(2/x)-4+2 // - (10/x)*x-(2/x)-4+2

((5*x)/x)*x+2/x-((10/x)*x)-4-2+4 = 0

((5*x)/x)*x+2/x-10-4-2+4 = 0

5*x^1+2*x^-1-12*x^0 = 0

(5*x^2-12*x^1+2*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^2-12*x^1+2*x^0) = 0

x^1

5*x^2-12*x+2 = 0

5*x^2-12*x+2 = 0

DELTA = (-12)^2-(2*4*5)

DELTA = 104

DELTA > 0

x = (104^(1/2)+12)/(2*5) or x = (12-104^(1/2))/(2*5)

x = (2*26^(1/2)+12)/10 or x = (12-2*26^(1/2))/10

x in { (12-2*26^(1/2))/10, (2*26^(1/2)+12)/10} 

x in { (12-2*26^(1/2))/10, (2*26^(1/2)+12)/10 }

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