5x/x-7=x+10/x-5

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Solution for 5x/x-7=x+10/x-5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(5*x)/x-7 = x+10/x-5 // - x+10/x-5

(5*x)/x-x-(10/x)-7+5 = 0

(5*x)/x-x-10*x^-1-7+5 = 0

3*x^0-1*x^1-10*x^-1 = 0

(3*x^1-1*x^2-10*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^1-1*x^2-10*x^0) = 0

x^1

3*x-x^2-10 = 0

3*x-x^2-10 = 0

DELTA = 3^2-(-10*(-1)*4)

DELTA = -31

DELTA < 0

x in { } 

x belongs to the empty set

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