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5x2+-28x+-12=0

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Solution for 5x2+-28x+-12=0 equation: 



5x^2+-28x+-12=0

We add all the numbers together, and all the variables

5x^2-28x=0

a = 5; b = -28; c = 0;
Δ = b2-4ac
Δ = -282-4·5·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{784}=28


x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-28}{2*5}=\frac{0}{10}
=0



x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+28}{2*5}=\frac{56}{10}
=5+3/5

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